Ever wanted to limit the number of returns you get from a MySQL Query? You want to show all of them, but you'd really like to show them spanning 2 or three or 15 pages for example... After sleeping on the bus, i discovered how to do this fairly easily.
By : nsfmc
<html>
<head>
<title>Page Lister</title>
<style type="text/css">
a { text-decoration: none }
body { color: #000; background-color: #fff}
</style>
</head>
<body bgcolor="#ffffff">
<?PHP
$PAGE = (isset($page)) ? $page : 1; #We hope that page, not PAGE is in the querystring,
#if not we set it here
$dbhost = "localhost"; # These are fairly self explanatory....
$dbname = "fillmein"; # You can remove these if you've already connected to a DB...
$dbuser = "fillmein";
$dbpass = "fillmein";
$dc = mysql_connect($dbhost,$dbuser,$dbpass); #Use $dc for debugging.
mysql_select_db($dbname,$dc); # Connect now, forget about it later.
$QUERY = "SELECT * FROM table"; ## You MUST change this :)!
$QRETURN= @mysql_query($QUERY);
$QNUM = @mysql_num_rows($QRETURN);
$DISPPAGE = 10; #DISPPAGE is the number of items displayed per page.
$NUMPAGES = ceil($QNUM / $DISPPAGE); #NUMPAGES to show how many pages you WILL get.
if($QRETURN): #Sanity check on query, only runs if valid query.
if($QNUM > 0): #We actually got some rows.
echo "<div align=\"right\">\n<font face=\"Tahoma, Geneva, sans-serif\" size=\"1\">\n";
for($i = 1; $i <= $NUMPAGES; $i++): #loop to print << 1 2 3... $NUMPAGES >>
if($i == 1 && $PAGE > 1) #Prints the << first to goto the previous page (not on page 1)
echo "<a href=\"$PHP_SELF?page=".($PAGE - 1)."\" onMouseOver=\"status='Go to the Previous Page';return true;\" onMouseOut=\"status=' ';return true;\">« </a>";
if($i == $PAGE) #Doesn't print a link itself, just prints page number
echo "<font color=\"#ff3333\"> $i </font>";
if($i != $PAGE) #Other links that aren't this page go here
echo "<a href=\"$PHP_SELF?page=$i\" onMouseOver=\"status='Go to Page $i';return true;\" onMouseOut=\"status=' ';return true;\"> $i </a>";
if($i == $NUMPAGES && $PAGE != $NUMPAGES) # Link for next page >> (not on last page)
echo "<a href=\"$PHP_SELF?page=".($PAGE + 1)."\" onMouseOver=\"status='Go to the Next Page';return true;\" onMouseOut=\"status=' ';return true;\"> »</a>";
endfor;
echo "</font>\n</div>\n";
echo "<font face=\"Verdana, Arial, Helvetica, sans-serif\" size=\"2\">\n";
$START = ($PAGE - 1) * $DISPPAGE;
mysql_data_seek($QRETURN,$START); #Moves the pointer to right row
#This loop will go until you a) reach $DISPPAGE or b) there aren't anymore entries
for($i = 1; $i <= $DISPPAGE && $ARET = @mysql_fetch_array($QRETURN); $i++):
$VAR = $ARET["col"]; #******** Here's the bit you should update! ********#
echo "$VAR\n<br><br>\n\n"; #echoes the field...
# Alternately, if you feel like numbering. I haven't tested this.
#echo "<b>".$START + ($i - 1)."</b>: $VAR\n<br><br>\n\n";
endfor;
echo "</font>\n";
endif;
if($QNUM == 0) #if we get no rows
echo "<div align=\"center\">The database is empty</div>\n";
endif;
if(!$QRETURN): # Bogus Query, or mysqld isn't running...
echo "<div align=\"center\">\n";
echo "<font face=\"Arial, Verdana, Helvetica, sans-serif\" color=\"#ff3333\" size=\"3\">\n";
echo "Either the database is down, or the query was invalid\n";
echo "</font>\n</div>\n";
endif;
?>
</body>
</html>
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